A divisibility rule is a way of determining whether a given number is divisible by a fixed number without performing the division.

We can use tests of divisibility to finding out the prime factors.

If a number has any of the digits 0, 2, 4, 6, 8 in its units place, then that number is divisible by 2.

**let’s say the number 3456**

The number 3456 has 6 in its unit place. So that **3456 number is divisible by 2.**

Mark saved Rs.1200 in this month. He wanted to buy two gifts for his brother and
sister. He thought to buy these gifts worth same cost. How would he spend his savings
on these two gifts?

**Mark** had Rs.1200. He wanted to buy two gifts from this savings.

As he divided Rs.1200 in two equal parts.

The number 1200 has 0 in its unit place. So that1200 is divisible by 2.

Now 1200/2= 600.

If the sum of digits of number is divisible by 3 then the number is divisible by 3.

**let’s say the number 3456.**

The sum of the digits in the number 3456 is 3+4+5+6= 18. 18 is divisible by 3.

**Hence, 3456 is divisible by 3.**

Jennifer decided to do the activity for Maths in the classroom. Classroom had total
78 students. She wanted to make 3 groups from the class with equal number of students.
What would she do?

**Classroom** had total 78 students.

Check the number 78 with test for divisibility by 3.

The sum of the digits in the number 78 is 7+8=15.

15 is divisible by 3.

Hence, 78 is divisible by 3.

Now, 78/3= 26

If the number formed by digits in the tens and units places is divisible by 4, then that number is also divisible by 4.

**let’s say the number 3112**

In the number 3112, the number formed by the digits in the tens and unit places
is 12.

The number 12 is divisible by 4 so that, the number 3112 is divisible by 4.

Rob has bundle of pages 5110. Would he able to distribute them with 4 clients
equally?

**In the number 5110**, the number formed by the digits in the tens and unit places
is 10.

The number 10 is not divisible by 4 so that, the number 5110 is not divisible by
4.

If a number has either 0 or 5 in its units place, then that number is divisible by 5.

**let’s say the number 3035.**

The number 3035 has 5 in its unit place. So that 3035 is divisible by 5.

If a number can be divided by the numbers 2 as well as 3, then that number is divisible by 6.

**1. let’s say the number 55128**

The number 55128 has 8 in the unit place. There it is divisible by 2. The sum of
the digits in the number 55128 is 5+5+1+2+8 = 21. 21 is divisible by 3. Therefore,
55128 is divisible by 6.

**2. let’s say the number 45120.**

The number 45120 has 0 in the unit place. There it is divisible by 2. The sum of
the digits in the number 45120 is 4+5+1+2+0= 12. 12 is divisible by 3. Therefore,
45120 is divisible by 6.

If the sum of the digits in a number is divisible by 9, then that number is divisible by 9.

**let’s say the number 55008.**

The sum of the digits in the number 55008 is 5+5+0+0+8= 18. 18 is divisible by
9. Therefore, 55008 is divisible by 9.

**let’s say the number 2247.**

The sum of the digits in the number 2247 is 2+2+4+7= 15. 15 is not divisible by
9. Therefore, 2247 is not divisible by 9.

If a number has 0 in its units place, then that number is divisible by 10.

**let’s say the number 3050.**

The number 3050 has 0 in its unit place. So that 3050 is divisible by 10.

If the difference between the sums obtained by adding alternate digits of the number is 0 or is divisible by 11 then that number is also divisible by 11.

**let’s say the number 1463.**

The sums of the alternate digits of the number 1463 are 1+6= 7 and 4+3= 7. the
difference between them is 7-7= 0. Therefore, 1463 is also divisible by 11.

**let’s say the number 8243**

The sums of the alternate digits of the number 8243 are 8+4= 12 and 2+3= 5. The
difference between them is 12-5= 7. 7 is not divisible by 11.Therefore, 8243 is
not divisible by 11.

The quotients obtained by dividing the number are the Divisors of number.

To find divisor of 15, divide 15 by 3.

We get 5 as quotients.

So that, 3 and 5 is the divisor of 15.

- Every number is divisible by number 1 and itself.

225 is divisible by 5. 225 / 5 = 45.

225 is divisible by 3. 225 / 3 = 75

225 is divisible by 9. 225 / 9 = 25

**Now every number is divisible by number 1 and itself. **

We will use tests of divisibility here.

**420 **is divisible by 2. 420/2 = 210.

**420 **is divisible by 10. 420/10 = 42.

**420 **is divisible by 5. **420 **/5 = 84.

**420 **is divisible by 3. **420 **/3 = 140

**420 **is divisible by 2 and 3. So that, **420 **is divisible by 6. **
420
**/6 = 70.

**Now every number is divisible by number 1 and itself**

We will use tests of divisibility here.

You can see that **8965 **has 5 in its unit place. Hence, **8965 **is divisible
by 5. **8965**/5 = 1993.

The sums of the alternate digits of the number **8965 **are 8+6= 14 and 9+5= 14.

The difference between them is 14-14= 0. Therefore, **8965 **is also divisible
by 11. **8965/11= 815**

**8965 is divisible by number 1 and itself.**

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