Mean, also called the arithmetic mean or average, is obtained by dividing the sum of all the numbers by the quantity of the numbers.

Find the mean of 3, 4 and 5

`(3 + 4 + 5)/6 = 12/6 = 2`

The basic formula of Mean is

`bar(X) = (sum_(i=1)^N X_i)/N `

Where,

`bar(X)` (read as "x" bar) - is the symbol for mean

∑ (the Greek letter sigma) - is the symbol for sum

`Χ_i` - is the sum of the numbers

N- is the quantity of numbers

We find the mean by applying the formula,

`bar(X) = (sumx)/N `

`bar(X)` = `(5 + 10 + 15 + 20 + 30 + 90) /6`

`bar(X)` = ` 170 /6`

`bar(X)` = `28.33`

So, the mean is `28.33`

Data can be represented as ungrouped or grouped.

It is data obtained in original / raw form.

Marks obtained by 22 students in Science exam are as follows:

80, 72, 80, 75, 60, 40, 60, 44, 45, 47, 62, 46, 42, 42, 41,50, 51, 72, 73, 84, 87, 85

When we organize the raw data and put it in groups (known as classes), it is called grouped data.

When we put the same data in a more condensed form, and mention the frequency of each group, then such a table is called grouped frequency distribution table.

Math scores | Frequency (f) |
---|---|

80-89 | 5 |

70-79 | 4 |

60-69 | 3 |

50-59 | 2 |

40-49 | 8 |

The formula for the calculation of mean of ungrouped data is given below:

` bar(X)`= `(sum_(i=1)^n x_i)/n `=` (x_1+x_2+...+x_n)/n`

Math scores | Frequency (f) |
---|---|

1 | 60 |

2 | 47 |

3 | 73 |

4 | 69 |

5 | 56 |

6 | 82 |

7 | 51 |

8 | 63 |

9 | 77 |

10 | 90 |

This states that 10 students got 66.8 marks on an average.

The mean is calculated as:

`bar(X)= (sumx)/n `

`sumx= 60+47+73+69+56+82+51+63+77+90`

`bar(X)= 668/10`

`bar(X) = 66.8`

No. of observations, n = 7

z`sum_(i=1)^7 x_i= 50 + 100 + 150 + 200 + 250 + 300 + 350 `

`sum_(i=1)^7 x_i= 1400`

`barX= (sum_(i=1)^7 x_i)/n `

`barX= 1400/7`

`barX= 200`

Data represented in the form of frequency distribution is called grouped data. The following table illustrates the result of an experiment in which a dice was rolled 20 times.Below values were recorded every time.

1,2,3,4,5,6

Math scores | Frequency (f) |
---|---|

1 | 4 |

2 | 6 |

3 | 2 |

4 | 2 |

5 | 5 |

6 | 1 |

Total = 20 |

We find the mean using the below formula:

`bar(X)= (sum_(i=1)^n fx_i)/(sum_(i=1)^n f_i)`

Math scores | Frequency (f) |
---|---|

1 | 4 |

2 | 6 |

3 | 2 |

4 | 2 |

5 | 5 |

6 | 1 |

Total = 20 |

The formula to determine the arithmetic mean of grouped data is :

`bar(X)= (sum_(i=1)^n fx_i)/(sum_(i=1)^n f_i)`

We find the values of f.x (by multiplying f with x) as shown below:

Number on the Dice (X) | Frequency (f) | f.X |
---|---|---|

1 | 4 | 4 |

2 | 6 | 12 |

3 | 2 | 6 |

4 | 2 | 8 |

5 | 5 | 25 |

6 | 1 | 6 |

`sum_(i=1)^6 f_i = 20` | `sum_(i=1)^6 fx_i = 61` |

Therefore

`bar(X)= (sum_(i=1)^6 fx_i)/(sum_(i=1)^6 f_i)`

`bar(X) = 61/( 20 )`

`bar(X) = 3.05 ~~ 3`

We round off the number to 3.

Classes (X) | Frequency (f) |
---|---|

0-9 | 7 |

10-19 | 4 |

20-29 | 8 |

30-39 | 5 |

40-49 | 9 |

50-59 | 7 |

60-69 | 10 |

Total= 50 |

We need to find the midpoint of each of the class using the below formula.

Midpoint = `text(Upper limit + Lower Limit)/2`,

Using this formula, we find the midpoint of each group as shown in the table below. These values are denoted by x in the table.

Number on the dice (X) | Frequency (f) | f.X |
---|---|---|

1 | 4 | 4 |

2 | 6 | 12 |

3 | 2 | 6 |

4 | 2 | 8 |

5 | 5 | 25 |

6 | 1 | 6 |

`sum_(i=1)^6 f_i = 20` | `sum_(i=1)^6 fx_i = 61` |

Next, we multiple each midpoint value with its corresponding value of frequency. The "f.x" values are recorded in a new column as shown in the following table.

Number on the classes | Frequency(f) | f.X |
---|---|---|

0-9 | 7 | 4.5 |

10-19 | 4 | 14.5 |

20-29 | 8 | 24.5 |

30-39 | 5 | 34.5 |

40-49 | 9 | 44.5 |

50-59 | 7 | 54.5 |

60-69 | 10 | 64.5 |

Total= 50 |

Therefore,

`bar(X)= (sum_(i=1)^7 fx_i)/(sum_(i=1)^7 f_i) `

`= 1885/(50) = 37.7`

© 2020 iPracticeMath | All Rights Reserved | Terms of Use.